From: Mike Keitz
;You have to have the 2 BCD digits in the low 4 bits of ;bcdh and bcdl, with the high 4 bits all zero. ;The result is place in bin. ;Note that it could be modified to just reuse one of the ;bcd locations to store the binary result. movfw bcdh movwf bin ;bin = bcdh clrc rlf bin, F ;bin = bcdh * 2 rlf bin, F ;bin = bcdh * 4 addwf bin, F ;bin = bcdh * 4 + bcdh = bcdh * 5 rlf bin, F ;Now bin = bcdh * 5 * 2 = bcdh * 10 movfw bcdl addwf bin, F ;Finally bin = bcdh*10 + bcdl
|file: /Techref/microchip/math/radix/bu2b-2d8b.htm, 1KB, , updated: 2012/11/20 13:36, local time: 2023/2/7 06:24,
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